Skip to main content

Minimum Swaps 2 HackerRank Solution | Java Solution

Minimum Swaps Two HackerRank Solution in Java

Minimum Swaps 2 Solution in Java

You are given an unordered array consisting of consecutive integers [1,2,3,....n] without any duplicates. You are allowed to swap any two elements. You need to find the minimum number of swaps required to sort the array in ascending order. 

For example, given the array arr = [7,1,3,2,4,5,6] we perform the following steps: 

i   arr                         swap (indices)
0   [7, 1, 3, 2, 4, 5, 6]   swap (0,3)
1   [2, 1, 3, 7, 4, 5, 6]   swap (0,1)
2   [1, 2, 3, 7, 4, 5, 6]   swap (3,4)
3   [1, 2, 3, 4, 7, 5, 6]   swap (4,5)
4   [1, 2, 3, 4, 5, 7, 6]   swap (5,6)
5   [1, 2, 3, 4, 5, 6, 7]

it took 5 swaps to sort the array.

See full description in HackerRank Website :-

 

public class MinimumSwaps2 {

    public static void main(String[] args) {
       
        Scanner sc = new Scanner(System.in);
        System.out.println("Enter array size");
        int arraySize = sc.nextInt();
       
        int array[] = new int[arraySize];
        System.out.println("Enter array values ");
        for (int i = 0; i < arraySize; i++) {
            array[i] = sc.nextInt();
        }
       
        int totalSwap = 0;
       
        // Loop through loop
        for (int i = 0; i < array.length; i++) {
           
            // Check if array index and value are matched or not
            if (array[i] != i+1) {
                int index = i;
               
                // Loop until index not matched array value
                while (array[index] != i+1) {
                    index++;
                }
               
                // Swap array value with finded value
                int temp = array[index];
                array[index] = array[i];
                array[i] = temp;
                totalSwap++;
            }
        }

        System.out.println(totalSwap);
    }
}

Output :-
Enter array size
5
Enter array values
2 3 4 1 5
Total Swaps: 3
---------------------

Enter array size
7
Enter array values
1 3 5 2 4 6 7
Total Swaps: 3


Explanation :-

  1. First loop through array and check if array value is matching with index or not (like index 1 is match with array value 1) if it matches then we don't need to swap the value.
  2. If it array index does not match with array value then goes into while loop.
  3. Checking which array index contains current index value
  4. After matching swap the values and increment the totalSwap variable.

Example :-

4
4 3 1 2

1 3 4 2 (Swap 4 and 1)
1 2 4 3 (Swap 2 and 3)
1 2 3 4 (Swap 3 and 4)


If you have still doubt in above explanation comment down. Thank You.

Other HackerRank Problems and Solutions :-


Comments

Popular posts from this blog

Plus Minus HackerRank Solution in Java | Programming Blog

Java Solution for HackerRank Plus Minus Problem Given an array of integers, calculate the ratios of its elements that are positive , negative , and zero . Print the decimal value of each fraction on a new line with 6 places after the decimal. Example 1 : array = [1, 1, 0, -1, -1] There are N = 5 elements, two positive, two negative and one zero. Their ratios are 2/5 = 0.400000, 2/5 = 0.400000 and 1/5 = 0.200000. Results are printed as:  0.400000 0.400000 0.200000 proportion of positive values proportion of negative values proportion of zeros Example 2 : array = [-4, 3, -9, 0, 4, 1]  There are 3 positive numbers, 2 negative numbers, and 1 zero in array. Following is answer : 3/6 = 0.500000 2/6 = 0.333333 1/6 = 0.166667 Lets see solution Solution 1 import java.io.*; import java.math.*; import java.security.*; import java.text.*; import java.util.*; import java.util.concurrent.*; import java.util.function.*; import java.util.regex.*; import java.util.stream.*; import static java.util.st

Flipping the Matrix HackerRank Solution in Java with Explanation

Java Solution for Flipping the Matrix | Find Highest Sum of Upper-Left Quadrant of Matrix Problem Description : Sean invented a game involving a 2n * 2n matrix where each cell of the matrix contains an integer. He can reverse any of its rows or columns any number of times. The goal of the game is to maximize the sum of the elements in the n *n submatrix located in the upper-left quadrant of the matrix. Given the initial configurations for q matrices, help Sean reverse the rows and columns of each matrix in the best possible way so that the sum of the elements in the matrix's upper-left quadrant is maximal.  Input : matrix = [[1, 2], [3, 4]] Output : 4 Input : matrix = [[112, 42, 83, 119], [56, 125, 56, 49], [15, 78, 101, 43], [62, 98, 114, 108]] Output : 119 + 114 + 56 + 125 = 414 Full Problem Description : Flipping the Matrix Problem Description   Here we can find solution using following pattern, So simply we have to find Max of same number of box like (1,1,1,1). And last